anonymous
  • anonymous
Need help. Problem says to rationalize and simplify 6 sq rt2 divided by square root 2-3
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
I am coming up with -12-18 square root 6 divided by 7
anonymous
  • anonymous
\[\frac{6\sqrt{2}}{\sqrt{2}-3}=\frac{6\sqrt{2}\times (\sqrt{2}+3)}{(\sqrt{2}-3)\times (\sqrt{2}+3)}=\frac{12+18\sqrt{2}}{-7}\]
anonymous
  • anonymous
Don't you need to get rid of the -7?

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anonymous
  • anonymous
no.
anonymous
  • anonymous
why need to? -7 is a rational number. (Why do we rationalize? Because to make the denominator a rational number)
anonymous
  • anonymous
understood bastax?
anonymous
  • anonymous
The example in the book shows getting rid of the -7 by multiplying by -1
anonymous
  • anonymous
Would my answer be correct if that was the case?
anonymous
  • anonymous
sometimes authors try to bring the negative sign upwards. But keeping -7 or 7 in denominator is just the same. The answer is rationalized as long as the denominator is a rational.
anonymous
  • anonymous
your answer is correct.
anonymous
  • anonymous
u can bring the negative sign on the top by multiplying up and down with -1, if ur tutor taught u so.
anonymous
  • anonymous
Awesome. Thank you!

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