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anonymous

  • 5 years ago

Need help. Problem says to rationalize and simplify 6 sq rt2 divided by square root 2-3

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  1. anonymous
    • 5 years ago
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    I am coming up with -12-18 square root 6 divided by 7

  2. anonymous
    • 5 years ago
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    \[\frac{6\sqrt{2}}{\sqrt{2}-3}=\frac{6\sqrt{2}\times (\sqrt{2}+3)}{(\sqrt{2}-3)\times (\sqrt{2}+3)}=\frac{12+18\sqrt{2}}{-7}\]

  3. anonymous
    • 5 years ago
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    Don't you need to get rid of the -7?

  4. anonymous
    • 5 years ago
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    no.

  5. anonymous
    • 5 years ago
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    why need to? -7 is a rational number. (Why do we rationalize? Because to make the denominator a rational number)

  6. anonymous
    • 5 years ago
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    understood bastax?

  7. anonymous
    • 5 years ago
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    The example in the book shows getting rid of the -7 by multiplying by -1

  8. anonymous
    • 5 years ago
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    Would my answer be correct if that was the case?

  9. anonymous
    • 5 years ago
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    sometimes authors try to bring the negative sign upwards. But keeping -7 or 7 in denominator is just the same. The answer is rationalized as long as the denominator is a rational.

  10. anonymous
    • 5 years ago
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    your answer is correct.

  11. anonymous
    • 5 years ago
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    u can bring the negative sign on the top by multiplying up and down with -1, if ur tutor taught u so.

  12. anonymous
    • 5 years ago
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    Awesome. Thank you!

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