A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 5 years ago

pls help.. a long straight rope lying on a floor is pulled along its length with uniform acceleration .If the velocities of the front & back ends of the rope when it passes through a particular point on the floor are 2 m/s & 4 m/s respectively, the velocity of the midpoint of the rope when it passes through the same point is a. 3 b. sqrt.10

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If v is the velocity of the midpoint. $$2*a*\frac l2 =v^2-(2)^2=(4)^2-v^2$$ which gives $$v=\sqrt{10} ms^{-1}$$

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.