anonymous
  • anonymous
derivate (x^(1/3)+x)/(x^(1/2))
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
find the derivative of this function, plz.
anonymous
  • anonymous
split it up over the denominator
anonymous
  • anonymous
its quicker than quotient rule

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ie f(x) = [ x^(1/3) / x^(1/2) ] + [ x / x^(1/2) ]
anonymous
  • anonymous
(1/3) -(1/2) = -1/6
amistre64
  • amistre64
(x^(1/3)+x) (x^(-1/2)) x^(1/3-1/2) + x^(1-1/2)
anonymous
  • anonymous
therefore f(x) = x^(-1/6) + x^(1/2)
anonymous
  • anonymous
then power rule
anonymous
  • anonymous
f ' (x) = (-1/6) x^(-7/6) +(1/2) x^(-1/2)
anonymous
  • anonymous
please i need the answer by hand writing. in pdf if possible.
amistre64
  • amistre64
then the best results would be for you to pick up a pencil and paper and write down what elec has done instead wanting someone to go out of their way even more for free...... just a thought.
shadowfiend
  • shadowfiend
Right on, amistre.

Looking for something else?

Not the answer you are looking for? Search for more explanations.