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anonymous
 5 years ago
please help...
'n' cells of emf 'E' & internal resistance 'r' is connected in series to an external resistance 'R'.What is its total emf, total resistance & current intensity ?????
anonymous
 5 years ago
please help... 'n' cells of emf 'E' & internal resistance 'r' is connected in series to an external resistance 'R'.What is its total emf, total resistance & current intensity ?????

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Owlfred
 5 years ago
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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well since you are connecting them in series, the net e.m.f adds up $$E_{net}=nE$$ Same is the case with the resistance of the e.m.fs $$r_{net}=nr$$ That gives $$I=\frac{E_{net}}{r_{net}+R}=\frac{nE}{nr+R} $$
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