A community for students.
Here's the question you clicked on:
 0 viewing
M
 5 years ago
double integral
M
 5 years ago
double integral

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What do you need answered??

M
 5 years ago
Best ResponseYou've already chosen the best response.0trying to use equation to write question but not working

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yeah, they blame it on user error lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1{SS} dx.dy ; [a,b] [c,d] works

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i saw a cute pic and figured... why not help lol

M
 5 years ago
Best ResponseYou've already chosen the best response.0when you switch from 1 to 2 for dx and 0 to lnx for dy you end up with 0 to ln2 and e^y to 2

M
 5 years ago
Best ResponseYou've already chosen the best response.0it's impossible to do this without equation lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1is it dx.dy order ; or dy.dx order?

M
 5 years ago
Best ResponseYou've already chosen the best response.0but shouldn't dy switch to 0 to 2?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1so your re adjusting the intervals right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1{S{Sdy}dx} ; x interval = [1,2] ; y interval = [0, ln(x)] originally right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1then teh easiest thing to do is graph it; with the lines y=0, y=ln(x), x=1, x=2

M
 5 years ago
Best ResponseYou've already chosen the best response.0when you switch shouldn't it be [0, 2] and [e^y, 0]

M
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i drew the pic but can't figure out the limits

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1this is the area we want, you agree?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1then we determine the switch this way right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1{S{S} dx} dy} ; new y = [0,e^2] then, we want it a straigh line ...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ln(2) = y and new x = [e^y, 2]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1new y = [0,ln(2)] new x = [e^y,2] ; you said the book has an answer?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1y = ln(2) at the top right? so new y = [0,ln(2)]

M
 5 years ago
Best ResponseYou've already chosen the best response.0that makes sense but when i look at another problem [0, 1] [4x, 4] dydx switches to [0, 4] [0, y/4] dxdy

M
 5 years ago
Best ResponseYou've already chosen the best response.0whoops ignore that it's [4, 0 ][0, sqrt x]dydx to [0, 2][4, y^2]dxdy

M
 5 years ago
Best ResponseYou've already chosen the best response.0[0, 4][0, sqrt x]dydx to [0, 2][y^2, 4]]dxdy

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1gonna make me draw another pic aintcha lol

M
 5 years ago
Best ResponseYou've already chosen the best response.0if i do it like the way you did it then should it new become [0, sqrt x][y^2, 4]dxdy?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1your just switching out the new for the old; it takes practice, but clearly define the old and new

M
 5 years ago
Best ResponseYou've already chosen the best response.0but the new limits would be [0, sqrt x][y^2, 4]dxdy

M
 5 years ago
Best ResponseYou've already chosen the best response.0but answer says [0, 2][y^2, 4]dxdy

M
 5 years ago
Best ResponseYou've already chosen the best response.0can you tell where i'm getting confused?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1look at the picture; the new limit goes to 0,2 becasue its no longer a part of the curve...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sqrt(x) is an old limit for an old y; that curve is no longer a part of the new y

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1just like old x = 0 is no longer a part of new x interval;

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1new y matches old x in that it is a limit that is defined from a point to point.... new x matches new y in that it is a limit from a curve to a point.....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its like reading a map backwards to get back home .... you have to reorient it to make sense

M
 5 years ago
Best ResponseYou've already chosen the best response.0i think im going to have to look at all the pictures again very slowly by myself lol

M
 5 years ago
Best ResponseYou've already chosen the best response.0thanks for the help! need to start from top again
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.