M
  • M
double integral
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
What do you need answered??
M
  • M
trying to use equation to write question but not working
amistre64
  • amistre64
yeah, they blame it on user error lol

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More answers

M
  • M
hmm i click and nothing
amistre64
  • amistre64
{SS} dx.dy ; [a,b] [c,d] works
anonymous
  • anonymous
hey amister!!!
amistre64
  • amistre64
hi ;)
amistre64
  • amistre64
i saw a cute pic and figured... why not help lol
M
  • M
when you switch from 1 to 2 for dx and 0 to lnx for dy you end up with 0 to ln2 and e^y to 2
M
  • M
it's impossible to do this without equation lol
amistre64
  • amistre64
is it dx.dy order ; or dy.dx order?
M
  • M
but shouldn't dy switch to 0 to 2?
M
  • M
going from dydx to dxdy
amistre64
  • amistre64
so your re adjusting the intervals right?
M
  • M
answer book has it 0 to ln2
M
  • M
switching the order
amistre64
  • amistre64
{S{Sdy}dx} ; x interval = [1,2] ; y interval = [0, ln(x)] originally right?
M
  • M
yeah
amistre64
  • amistre64
then teh easiest thing to do is graph it; with the lines y=0, y=ln(x), x=1, x=2
M
  • M
when you switch shouldn't it be [0, 2] and [e^y, 0]
M
  • M
i mean [0, 2] and [e^y, 2]
amistre64
  • amistre64
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M
  • M
yeah i drew the pic but can't figure out the limits
amistre64
  • amistre64
this is the area we want, you agree?
1 Attachment
M
  • M
very nice yes
amistre64
  • amistre64
then we determine the switch this way right?
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M
  • M
yeah
amistre64
  • amistre64
{S{S} dx} dy} ; new y = [0,e^2] then, we want it a straigh line ...
amistre64
  • amistre64
ln(2) = y and new x = [e^y, 2]
amistre64
  • amistre64
new y = [0,ln(2)] new x = [e^y,2] ; you said the book has an answer?
M
  • M
yeah
amistre64
  • amistre64
y = ln(2) at the top right? so new y = [0,ln(2)]
M
  • M
that makes sense but when i look at another problem [0, 1] [4x, 4] dydx switches to [0, 4] [0, y/4] dxdy
amistre64
  • amistre64
1 Attachment
M
  • M
whoops ignore that it's [4, 0 ][0, sqrt x]dydx to [0, 2][4, y^2]dxdy
M
  • M
[0, 4][0, sqrt x]dydx to [0, 2][y^2, 4]]dxdy
M
  • M
^^ that's correct one lol
amistre64
  • amistre64
gonna make me draw another pic aintcha lol
M
  • M
if i do it like the way you did it then should it new become [0, sqrt x][y^2, 4]dxdy?
M
  • M
lol you dont have to
amistre64
  • amistre64
but I did lol
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M
  • M
yeah
M
  • M
this is so confusing
amistre64
  • amistre64
1 Attachment
amistre64
  • amistre64
your just switching out the new for the old; it takes practice, but clearly define the old and new
M
  • M
but the new limits would be [0, sqrt x][y^2, 4]dxdy
M
  • M
but answer says [0, 2][y^2, 4]dxdy
M
  • M
can you tell where i'm getting confused?
amistre64
  • amistre64
look at the picture; the new limit goes to 0,2 becasue its no longer a part of the curve...
amistre64
  • amistre64
sqrt(x) is an old limit for an old y; that curve is no longer a part of the new y
amistre64
  • amistre64
just like old x = 0 is no longer a part of new x interval;
amistre64
  • amistre64
new y matches old x in that it is a limit that is defined from a point to point.... new x matches new y in that it is a limit from a curve to a point.....
amistre64
  • amistre64
its like reading a map backwards to get back home .... you have to reorient it to make sense
M
  • M
i think im going to have to look at all the pictures again very slowly by myself lol
M
  • M
thanks for the help! need to start from top again
amistre64
  • amistre64
good luck ;)

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