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anonymous
 5 years ago
double integral
anonymous
 5 years ago
double integral

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What do you need answered??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0trying to use equation to write question but not working

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yeah, they blame it on user error lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm i click and nothing

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1{SS} dx.dy ; [a,b] [c,d] works

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i saw a cute pic and figured... why not help lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you switch from 1 to 2 for dx and 0 to lnx for dy you end up with 0 to ln2 and e^y to 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's impossible to do this without equation lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1is it dx.dy order ; or dy.dx order?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but shouldn't dy switch to 0 to 2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0going from dydx to dxdy

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1so your re adjusting the intervals right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0answer book has it 0 to ln2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1{S{Sdy}dx} ; x interval = [1,2] ; y interval = [0, ln(x)] originally right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1then teh easiest thing to do is graph it; with the lines y=0, y=ln(x), x=1, x=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you switch shouldn't it be [0, 2] and [e^y, 0]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean [0, 2] and [e^y, 2]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i drew the pic but can't figure out the limits

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1this is the area we want, you agree?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1then we determine the switch this way right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1{S{S} dx} dy} ; new y = [0,e^2] then, we want it a straigh line ...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ln(2) = y and new x = [e^y, 2]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1new y = [0,ln(2)] new x = [e^y,2] ; you said the book has an answer?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1y = ln(2) at the top right? so new y = [0,ln(2)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that makes sense but when i look at another problem [0, 1] [4x, 4] dydx switches to [0, 4] [0, y/4] dxdy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whoops ignore that it's [4, 0 ][0, sqrt x]dydx to [0, 2][4, y^2]dxdy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0[0, 4][0, sqrt x]dydx to [0, 2][y^2, 4]]dxdy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0^^ that's correct one lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1gonna make me draw another pic aintcha lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if i do it like the way you did it then should it new become [0, sqrt x][y^2, 4]dxdy?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1your just switching out the new for the old; it takes practice, but clearly define the old and new

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the new limits would be [0, sqrt x][y^2, 4]dxdy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but answer says [0, 2][y^2, 4]dxdy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you tell where i'm getting confused?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1look at the picture; the new limit goes to 0,2 becasue its no longer a part of the curve...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sqrt(x) is an old limit for an old y; that curve is no longer a part of the new y

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1just like old x = 0 is no longer a part of new x interval;

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1new y matches old x in that it is a limit that is defined from a point to point.... new x matches new y in that it is a limit from a curve to a point.....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its like reading a map backwards to get back home .... you have to reorient it to make sense

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think im going to have to look at all the pictures again very slowly by myself lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks for the help! need to start from top again
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