anonymous
  • anonymous
looking to integrate a differential equation on both sides... d^2C/dz^2 = -zA* dC/dz how would I go about doing this?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Owlfred
  • Owlfred
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anonymous
  • anonymous
thanks! i'll be sure to give credit where credit is due. just to let you know, I simplified the constants in the equation into "A"
amistre64
  • amistre64
you replied to an automated message that really does nothing but post that you have aquestion in the chatroom box :)

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amistre64
  • amistre64
there you are :)
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anonymous
  • anonymous
thanks I noticed that when i clicked around. need an answer though!
amistre64
  • amistre64
d^2C/dz^2 = -zA* dC/dz hmm.... havent done to many of these so I dont know alot of the techniques, except for swapping variables when doing a first derivative..
anonymous
  • anonymous
its a secondary order differential equation.
amistre64
  • amistre64
C'' = -zA C' ...
amistre64
  • amistre64
Id say divide both sides by C'... but thats just a guess :)
amistre64
  • amistre64
its outta my league.... good luck with it :)
anonymous
  • anonymous
d^2C/dz^2 = -zA* dC/dz (D^2+Az)C=0 where D=d/dz
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=dC%28dC%2Fdz%29%2Fdz+%3D+-zA+%28dC%2Fdz%29
anonymous
  • anonymous
thanks anyway. its for transport phenomenon in biological systems :P
anonymous
  • anonymous
solution says that form is in a form of a natural exponential. can anyone explain?
anonymous
  • anonymous
i tried to recall the solution of higher order DE, but could not,away from it for a long time,i just remember the formation of auxilliary eq

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