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anonymous
 5 years ago
what is the limit as x approaches 0 when ((1cosx)^2)/x
anonymous
 5 years ago
what is the limit as x approaches 0 when ((1cosx)^2)/x

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02(1cosx) . sin(x) = 0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0otherwise you expand the top and see what you can do to it..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0((1cosx)(1cosx))/x = 0?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01 2cos(X) + cos^2(x)  .... x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0doesn't (1cosx)/x = o

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dunno; its been so long since I tried it the hard way :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you could try squeeze this on a graph

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=lim {x+to+0+}%28%281cosx%29^2%29%2Fx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But, (1cosx)/x times (1cosx)/x = (1cosx)^2 / x^2.......

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Why would you do that?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i dunno why it cuts it short; but copy paste that link itno your address bar

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amogh  I'm just pointing out that I'm doing it wrong...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, x will go with either of them, not both of them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amistre64: do you like ff4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sh@t! I did the problem wrong on my test then.......

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you for the Wolfram alpha link amistre64. How much is that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I answered "0" but I didn't do my work correctly (analytically), so I get the problem wrong
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