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rearrange 5x^ 2 +7x + 2 = 0 Factorising: (5x +2)(x+1)=0 x = -2/5 , -1
5x²+7x+2=0 D=b^2-4ac Same way as the other 1
oh! I assumed u wanted to solve it!
if ur factorising it is right u have solved it :)
yeah i know but did tina want to know the value of the determinant?
i have explained her earlier wht should she put instead of a,b and c....she can find the value herself i guess :)
D=49-4*5*2=9 X1=(-b+sqrD)/2a=(-7+3)/2*5=-4/10=-2/5 X2=(-b-sqrD)/2a=(-7-3)/2*5=-10/10=-1 :)
Put the x's to one side 5x² +7x = -2 ; divide out the 5 x^2 + (7/5)x = (-2/5) ; complete the square x^2 +(7/5)x+ (7/10)^2 = (-2/5) + (7/10)^2 ; clean it up (x+7/10)^2 = 9/100 ; sqrt the sides x+7/10 = +- 3/10 ; -7/10 x = -7/10 +- 3/10 x = -10/10 , and x = -4/10
x = -1, and x = -2/5
hmmmm.....i didn't know this way of solving this....(my way is shorter and better anyway :P )
completing the square is how we generalize going from: ax^2 +bx +c <-> x = (-b +- sqrt(b^2-4ac))/2a
there u go! solving by factorising, the general formula and completing the square!!
they first learn to "complete the square" so that you understand how the quad fromula is derived
otherwise, its simplying teaching to "FOIL" and they learn a memorization technique and remain ignorant about how or why it works :)
''Thnx a loot" X(
How do I get to SanJose from here? I dunno, but Ill know when were there lol
U mean u'll know when u'll** be there? O.o