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anonymous

  • 5 years ago

sin 0= cos 0= tan 0=

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  1. anonymous
    • 5 years ago
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  2. angela210793
    • 5 years ago
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    sin0=0 cos0=1 tan0=0/1=0

  3. anonymous
    • 5 years ago
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    about cos 1/?

  4. angela210793
    • 5 years ago
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    wht abt cos1?

  5. anonymous
    • 5 years ago
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    so it is 1/0 or not because i have to find the ration of this problem

  6. anonymous
    • 5 years ago
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    You are saying sin 0 but you mean

  7. anonymous
    • 5 years ago
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    you mean sin theta?

  8. anonymous
    • 5 years ago
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    yea i support to be 0 with cross but oh well and what sin theta..

  9. anonymous
    • 5 years ago
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    What is your question, when you ask more than one question in same post it becomes confusing. What is your question now?

  10. anonymous
    • 5 years ago
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    when i saw the picture of this problem which i don't know what to do with this..

  11. anonymous
    • 5 years ago
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    The (6,8) is the lengths. 6 is adjacent, 8 is opposite. From those two use pythagorean theorem to find the hypothenuse.

  12. anonymous
    • 5 years ago
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    oh and i need the ratio of this

  13. anonymous
    • 5 years ago
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    First find the hypotenuse, so that you have all the lengths of the triangles. You remember how to find that?

  14. anonymous
    • 5 years ago
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    like

  15. anonymous
    • 5 years ago
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    a2+b2=c2 right

  16. anonymous
    • 5 years ago
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    Yes

  17. anonymous
    • 5 years ago
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    with 6 and 10

  18. anonymous
    • 5 years ago
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    6 and 8. Draw the triangle on a piece of paper and fill it out. The x leg or adjacent is 6, the y leg or opposite is 8.

  19. anonymous
    • 5 years ago
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    6sq+xsq=8sq

  20. anonymous
    • 5 years ago
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    6^2+8^2=hypotenuse^2

  21. anonymous
    • 5 years ago
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    i got 10

  22. anonymous
    • 5 years ago
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    So draw your triangle and you have all the info to find sin, cos, etc

  23. anonymous
    • 5 years ago
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    Sorry

  24. anonymous
    • 5 years ago
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    sorry for...

  25. anonymous
    • 5 years ago
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    repeated posts

  26. anonymous
    • 5 years ago
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    that a ok

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