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anonymous
 5 years ago
Please help...Use the quadratic and a calculator to solve the following equation. Round intermediate calculations and final answers to two decimal places. 6.25y^2 + 12y + 5.76 = 0
i got y = .96, 96 but it was wrong should i round up to 1, 1
anonymous
 5 years ago
Please help...Use the quadratic and a calculator to solve the following equation. Round intermediate calculations and final answers to two decimal places. 6.25y^2 + 12y + 5.76 = 0 i got y = .96, 96 but it was wrong should i round up to 1, 1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you require the answer correct to dec places to do not iround intermediate results to 2 dp's

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right so I dont understand the statement Round intermediate calculations and final answers to two decimal places

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02 dec places i meant to say

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is it bcuz it is saying Use the quadratic and a calculator to solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i make the solutios 0.96

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is only one solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you think incluce the 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can a solution set have only one thing in it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.06.25y^2 + 12y + 5.76 = 0 Rationalize the coefficients. \[\frac{25}{4}y^2+12y+\frac{144}{25}=0\]Multiply each side by 100 and simplify.\[625 y^2+1200 y+576=0 \]Use the binomial theorem or, to pull a rabbit out of the hat:\[625 y^2+1200 y+576=(25 y+24)^2 \]\[y=\frac{24}{25}\text{ }\text{or}\text{ }0.96 \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you graph this function it will just touch the x axis at 0.96

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I stand corrected. Yes, the sign is negative. Thank you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you are saying that the only solution in the solution set is 0.96??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There are two solutions, each with identical values.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so both would be 0.96

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but I probably only need to enter it once?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the books always say two identical solutions but to be honest i dont understand why

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Woohoo it was correct...thank you both sooooo much!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I use Mathematica to do the calculations.\[\text{Solve}\left[(25 y+24)^2\text{==}0,y\right]=\left\{\left\{y\to \frac{24}{25}\right\},\left\{y\to \frac{24}{25}\right\}\right\} \]Notice that it returned two values for y. I would put down as an answer, x = 0.96 twice. Does this answer you questions?
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