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anonymous

  • 5 years ago

Please help...Use the quadratic and a calculator to solve the following equation. Round intermediate calculations and final answers to two decimal places. 6.25y^2 + 12y + 5.76 = 0 i got y = .96, -96 but it was wrong should i round up to 1, -1

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  1. anonymous
    • 5 years ago
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    if you require the answer correct to dec places to do not iround intermediate results to 2 dp's

  2. anonymous
    • 5 years ago
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    right so I dont understand the statement Round intermediate calculations and final answers to two decimal places

  3. anonymous
    • 5 years ago
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    2 dec places i meant to say

  4. anonymous
    • 5 years ago
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    Is it bcuz it is saying Use the quadratic and a calculator to solve

  5. anonymous
    • 5 years ago
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    i make the solutios -0.96

  6. anonymous
    • 5 years ago
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    there is only one solution

  7. anonymous
    • 5 years ago
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    so you think incluce the 0

  8. anonymous
    • 5 years ago
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    can a solution set have only one thing in it?

  9. anonymous
    • 5 years ago
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    yes

  10. anonymous
    • 5 years ago
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    6.25y^2 + 12y + 5.76 = 0 Rationalize the coefficients. \[\frac{25}{4}y^2+12y+\frac{144}{25}=0\]Multiply each side by 100 and simplify.\[625 y^2+1200 y+576=0 \]Use the binomial theorem or, to pull a rabbit out of the hat:\[625 y^2+1200 y+576=(25 y+24)^2 \]\[y=\frac{24}{25}\text{ }\text{or}\text{ }0.96 \]

  11. anonymous
    • 5 years ago
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    if you graph this function it will just touch the x axis at -0.96

  12. anonymous
    • 5 years ago
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    I stand corrected. Yes, the sign is negative. Thank you.

  13. anonymous
    • 5 years ago
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    ok

  14. anonymous
    • 5 years ago
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    so you are saying that the only solution in the solution set is -0.96??

  15. anonymous
    • 5 years ago
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    There are two solutions, each with identical values.

  16. anonymous
    • 5 years ago
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    so both would be -0.96

  17. anonymous
    • 5 years ago
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    yes

  18. anonymous
    • 5 years ago
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    but I probably only need to enter it once?

  19. anonymous
    • 5 years ago
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    the books always say two identical solutions but to be honest i dont understand why

  20. anonymous
    • 5 years ago
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    Woohoo it was correct...thank you both sooooo much!!!

  21. anonymous
    • 5 years ago
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    I use Mathematica to do the calculations.\[\text{Solve}\left[(25 y+24)^2\text{==}0,y\right]=\left\{\left\{y\to -\frac{24}{25}\right\},\left\{y\to -\frac{24}{25}\right\}\right\} \]Notice that it returned two values for y. I would put down as an answer, x = -0.96 twice. Does this answer you questions?

  22. anonymous
    • 5 years ago
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    no probs popcorn

  23. anonymous
    • 5 years ago
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    Your welcome.

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