## anonymous 5 years ago y=e^sinx

1. nowhereman

mmh, and what if I told you $$y=e^{\cos x}$$ ?

2. dumbcow

do you need to solve for x? graph this?

3. anonymous

if you are asking for the derivative of the expression, like you were in the last question you asked, then: d/dx e^u = e^u * du/dx, so: derivative of e^sinx = (e^sinx )*cosx

4. anonymous

yaaa