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anonymous

  • 5 years ago

find the sum of even integers between 1 and 60

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  1. anonymous
    • 5 years ago
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    use a calculator and count it manualy.

  2. anonymous
    • 5 years ago
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    i think it's around >1000

  3. anonymous
    • 5 years ago
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    i mean <1000

  4. anonymous
    • 5 years ago
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    (60^2 + 60 )/2

  5. anonymous
    • 5 years ago
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    oops

  6. anonymous
    • 5 years ago
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    i am wrong

  7. anonymous
    • 5 years ago
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    all "even" would be (60^2 + 60) /4 ???

  8. anonymous
    • 5 years ago
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    There are 30 even integers between 1 and 60. The first and last pair add to 62. So there are 15 pairs of integers who's sum is 62. Therefore the total is 62 * 15 = 930

  9. nowhereman
    • 5 years ago
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    No, you are approaching this wrong. Even between 1 and 60 are 2, 4, 6, ..., 60 so 2*(1, 2, 3, ..., 30) thus you get the sum 2*30*31/2 = 30*31 = 930

  10. anonymous
    • 5 years ago
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    ^ you are right, thanks for correction

  11. anonymous
    • 5 years ago
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    this is an arithmetic sequence of the following form a = 2n from n = 1 to n = 30. now use the formula for the arithmetic series: sum = (n/2) * (last term + first term) so sum = (30/2) * (2+30) = 480

  12. anonymous
    • 5 years ago
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    I think you mean 30/2 * (2+60)

  13. anonymous
    • 5 years ago
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    sorry sum = (30/2) *(2 + 60)

  14. anonymous
    • 5 years ago
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    930

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