anonymous
  • anonymous
find the sum of even integers between 1 and 60
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
use a calculator and count it manualy.
anonymous
  • anonymous
i think it's around >1000
anonymous
  • anonymous
i mean <1000

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anonymous
  • anonymous
(60^2 + 60 )/2
anonymous
  • anonymous
oops
anonymous
  • anonymous
i am wrong
anonymous
  • anonymous
all "even" would be (60^2 + 60) /4 ???
anonymous
  • anonymous
There are 30 even integers between 1 and 60. The first and last pair add to 62. So there are 15 pairs of integers who's sum is 62. Therefore the total is 62 * 15 = 930
nowhereman
  • nowhereman
No, you are approaching this wrong. Even between 1 and 60 are 2, 4, 6, ..., 60 so 2*(1, 2, 3, ..., 30) thus you get the sum 2*30*31/2 = 30*31 = 930
anonymous
  • anonymous
^ you are right, thanks for correction
anonymous
  • anonymous
this is an arithmetic sequence of the following form a = 2n from n = 1 to n = 30. now use the formula for the arithmetic series: sum = (n/2) * (last term + first term) so sum = (30/2) * (2+30) = 480
anonymous
  • anonymous
I think you mean 30/2 * (2+60)
anonymous
  • anonymous
sorry sum = (30/2) *(2 + 60)
anonymous
  • anonymous
930

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