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anonymous

  • 5 years ago

3px (p + x + 2px)

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. anonymous
    • 5 years ago
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    If you aren't solving for x, and simply distributing, 3p^2x + 3px^2 + 6p^2x^2

  3. anonymous
    • 5 years ago
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    lucasmedina10 is correct! Can you break it down to show me how you did it? Thanks

  4. anonymous
    • 5 years ago
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    polpak come back to my question

  5. anonymous
    • 5 years ago
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    Just multiply the 3px by each of the terms in the sum: \[3px (p + x + 2px)\] \[=3px(p) + 3px(x) + 3px (2px)\] \[=3p^2x + 3px^2 + (3\cdot 2)p^2x^2\] \[=3p^2x + 3px^2 +6p^2x^2\]

  6. anonymous
    • 5 years ago
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    oh sorry it was just an expression and need siplification

  7. anonymous
    • 5 years ago
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    So, looking at (p + x + 2px) you can see there are three "parts" to the expression. 3px (p + x + 2px) is asking you to multiply each part by 3px and fitting it into a simplified expression. So first multiply 3px by p. Then multiply 3px by x, and lastly multiply 3px by 2px. 1. When you multiply 3px by p, you get 3p^2x 2. When you multiply 3px by x, you get 3px^2 3. When you multiply 3px by 2px, you get 6p^2x^2 Now put it all together by adding them! Since they are all positive, you can easily use plus signs. That is how you get the answer 3p^2x + 3px^2 + 6p^2x^2.

  8. anonymous
    • 5 years ago
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    thanks

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