anonymous
  • anonymous
Find the equation of a polynomial function of lowest degree with real coefficients that has 6 and 3 - 2i as solutions.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Owlfred
  • Owlfred
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amistre64
  • amistre64
(x-6)(x-(3-2i))
amistre64
  • amistre64
(x-6)(x-3+2i) x^2 -3x +2xi -6x -12i+18 -------------------- x^2 -9x +18 +(2xi -12i)

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More answers

anonymous
  • anonymous
amistre: I dont think that this is with real coefficients
amistre64
  • amistre64
im working on it lol
anonymous
  • anonymous
I got it now i just forgot the first step
anonymous
  • anonymous
ok, cool :-)
amistre64
  • amistre64
cool; was I close?
amistre64
  • amistre64
i think we square this part tho right? 3 - 2i
amistre64
  • amistre64
its a cubic; with a bend above the line..
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=%28x-6%29%28x-3%2B2i%29^2 might be useful
anonymous
  • anonymous
Well when you have (3-2i) my definition you also have the conjugate (3+2i)
anonymous
  • anonymous
*by definition*
anonymous
  • anonymous
if your curious it was x^3-12x^2+49x-78
anonymous
  • anonymous
f(x) = " "
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=%28x-6%29%28x-%283-2i%29%29%28x-%283%2B2i%29%29
amistre64
  • amistre64
i was curious :) but yeah, thats what I came up with eventually

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