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anonymous
 5 years ago
Trignometric substitutio of the indefinite integral x^3*sqrt(16+x^2)dx
anonymous
 5 years ago
Trignometric substitutio of the indefinite integral x^3*sqrt(16+x^2)dx

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Owlfred
 5 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so far this is what i have

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0http://answers.yahoo.com/question/index?qid=20080508091701AAA0Mq0 im fixing to have dinner this link should help you with the rest im sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer should be [(16x^2)^5/2]/5[16(16+x^2)^3/2]/3+C

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0you should also put your answer back in terms of x i might be back on later if you haven't figured it out by then k?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k thanks for your help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you please help me?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre its really tough

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x^3*sqrt(16+x^2) dx; yeah, it can be..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.164 tan^3(t) * 4 sec(t) dt ; just gotta determine the dt now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its 4sec^2 theta dtheta

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.14sec^2(t) dt = dx right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.164 tan^3(t) * 16sec^3(t) dt then right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i put the answer above for reference, this problem is driving me crzy

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11024 (tan(t)sec(t))^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you do it on your own and see if you get that?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=int%2864+tan^3%28t%29+*+16sec^3%28t%29%29+dt

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1I aint got the time tonight, libraries closing soon but wolfram gives steps

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=int%28x^3+sqrt%2816%2Bx^2%29%29dx or this for the original

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You've got it. You've worked your way to a function that can be integrated.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Integral (sec theta tan theta)^3=sec^3 theta. Now you have to convert back. Good job Amistre. He just had to run and didn't have time to interpret it.
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