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anonymous

  • 5 years ago

Find the derivative of the function f(x) = (t^5-3t^3+2t^2e1)/2t^2

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  1. anonymous
    • 5 years ago
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    You can use http://www.wolframalpha.com/input/?i=derivative+of+%28t^5-3t^3%2B2t^2e1%29%2F2t^2

  2. anonymous
    • 5 years ago
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    thank you

  3. anonymous
    • 5 years ago
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    You're welcome :D

  4. anonymous
    • 5 years ago
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    I'm not understandint their answer i didnt get it like that i divided everything by 2t^2

  5. anonymous
    • 5 years ago
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    (f/g)' = (f'*g - f*g')/g^2

  6. anonymous
    • 5 years ago
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    huh?

  7. anonymous
    • 5 years ago
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    and its suppose to be h(t) sorry i dont know if that makes a difference

  8. anonymous
    • 5 years ago
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    and its suppose to be h(t) sorry i dont know if that makes a difference

  9. anonymous
    • 5 years ago
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    This is the rule what you must use

  10. anonymous
    • 5 years ago
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    we're suppose to use the power rule we didnt learn the quotient rule yet

  11. anonymous
    • 5 years ago
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    Then hmm wait a moment

  12. anonymous
    • 5 years ago
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    3/2 t^2 -3/2te^1

  13. anonymous
    • 5 years ago
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    thats what i got but i'm not sure about the e (natural number)

  14. anonymous
    • 5 years ago
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    (f ° g)' = (f' ° g) g' and this rule you know?

  15. anonymous
    • 5 years ago
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    nope

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