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anonymous
 5 years ago
assuming I=50p^2=1000p, what would be a good charge for a weekly bus pass to maximize income sails ? (quadratic functions stuff)
anonymous
 5 years ago
assuming I=50p^2=1000p, what would be a good charge for a weekly bus pass to maximize income sails ? (quadratic functions stuff)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Change the equation into standard form. i = 50p^2 +1000p Transform the equation into vertex form. i = 50(p20)^2 Now since the parabola opens down, you can find the maximum value by finding where the vertex lies on the graph. The vertex is (20,0).
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