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  • 5 years ago

assuming I=50p^2=1000p, what would be a good charge for a weekly bus pass to maximize income sails ? (quadratic functions stuff)

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  1. anonymous
    • 5 years ago
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    Change the equation into standard form. i = -50p^2 +1000p Transform the equation into vertex form. i = -50(p-20)^2 Now since the parabola opens down, you can find the maximum value by finding where the vertex lies on the graph. The vertex is (20,0).

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