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wow, this one is thermodynamics right?

yes

The heat associated with a certain mass changing temperature is

m*c*(dT)

the energy change in the water has to equal the energy change in the metal

Qm=140*c*(70-10)
Qw=220*4.186*(10-0)

so would i be solving the equation that you suggested i'm confused

Have you learned the heat/energy required to change the temperature of a substance?

no i don't quite understand how to solve problems like these.

the magnitude of the heat has to be the same for both the metal and the water

The magnitude of the heat is the same in both due to conservation of energy

so basically what would be the numbers in the equation to plug into the problem if is the same.

Your final equation would look like:
140*c*(70-10)=220*4.186*(10-0)
140*60*c=220*10*4.186

and you want to find c in J/gC

so how would i find c

140*60*c=220*10*4.186
8400*c=9209.2
c=9209.2/(8400)
c=1.1 J/gC

1.0963 would be c

yeah

so what units should i use for this problem?

that c is J/(gC) or Joules per gram degree Celsius

the energy in Joules it takes to change the temperature of 1 gram of metal 1 degree celsius

so would this be the same as 1.0963 cal/g degree Celsius ?

no 1 cal= 4.186 Joules

if you want calories divide your answer by 4.186

i don't think my answer is right

i have 0.2619

yep I think that's good

why dont you think it is right

im not sure what you mean

like should it say 0.2619 cal/g degrees Celsius, does that sound right?

oh yeah those are the units for specific heat

thank you so much I got it right thanks

you're welcome :)