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When a 140g piece of metal at 70 degrees C is
placed in 220g of water at 0 degrees C, the metal
is cooled, and the water is warmed and
both come to a final temperature of 10=C.
What is the specific heat of the metal?
?
 2 years ago
 2 years ago
When a 140g piece of metal at 70 degrees C is placed in 220g of water at 0 degrees C, the metal is cooled, and the water is warmed and both come to a final temperature of 10=C. What is the specific heat of the metal? ?
 2 years ago
 2 years ago

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OwlfredBest ResponseYou've already chosen the best response.0
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 2 years ago

lorizoliBest ResponseYou've already chosen the best response.0
The heat exchanged between the metal and the water is the same (assuming that this is a closed system (which it isn't by the way)). Therefore: \[C _{water}*m _{water}*\Delta T_{water} = C_{metal}*m_{metal}*\Delta T_{metal}\] \[C_{metal} = C_{water}m_{water}\Delta T_{water}/(m_{metal}\Delta T_{metal}) = 1.16 KJ/kgK\] for example sand has similar specific heat.
 2 years ago
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