Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

818jasmine

  • 4 years ago

When a 140g piece of metal at 70 degrees C is placed in 220g of water at 0 degrees C, the metal is cooled, and the water is warmed and both come to a final temperature of 10=C. What is the specific heat of the metal? ?

  • This Question is Closed
  1. Owlfred
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. lorizoli
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The heat exchanged between the metal and the water is the same (assuming that this is a closed system (which it isn't by the way)). Therefore: \[C _{water}*m _{water}*\Delta T_{water} = C_{metal}*m_{metal}*\Delta T_{metal}\] \[C_{metal} = C_{water}m_{water}\Delta T_{water}/(m_{metal}\Delta T_{metal}) = 1.16 KJ/kgK\] for example sand has similar specific heat.

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy