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  • 5 years ago

When a 140g piece of metal at 70 degrees C is placed in 220g of water at 0 degrees C, the metal is cooled, and the water is warmed and both come to a final temperature of 10=C. What is the specific heat of the metal? ?

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  1. Owlfred
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    The heat exchanged between the metal and the water is the same (assuming that this is a closed system (which it isn't by the way)). Therefore: \[C _{water}*m _{water}*\Delta T_{water} = C_{metal}*m_{metal}*\Delta T_{metal}\] \[C_{metal} = C_{water}m_{water}\Delta T_{water}/(m_{metal}\Delta T_{metal}) = 1.16 KJ/kgK\] for example sand has similar specific heat.

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