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bro whats the base equation again, something like pi int .... of the derivative squared?

idk if that matters

i have my integral calculus last semester.

y=+or- sqrtx , y=x/2 to make it simpler

come on guys, this isnt that hard.

wait for a while, i'm solving it.

what is really the given? it is lacking.

thats it

really?

they meet at (0,0)

got it.

thats one yes, and then they cross again

the answer is

8pi over 3

where do the two curves cross?

the limits are 0 and 2.

how

just substitute x=y^2 to x=2y
that will become, y^2-2y=0
y(y-2)=0
y=0
y=2

okay, let me double check now

i had a mistake, the answer must be 10pi/3

almost have it

okay,
i have the solution but i have a hard time encoding it.

whats (2^1.5)/(2/3) -1

i dont have my calculator :/

3.242640687

okay thats what i got... where did you get pi from?

im looking in the back of the book for the answer to see whos right.

okay i did it waaaay wrong haha

back of the book says 64pi/15

is it correct now?

is it the answer on the book?

64pi/15, so its close

okay im too tired for this, thanks for the help