anonymous
  • anonymous
volume of cylindrical shells (calculus): y^2=x, x=2y rotate about y axis
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
bro whats the base equation again, something like pi int .... of the derivative squared?
anonymous
  • anonymous
idk if that matters
anonymous
  • anonymous
i have my integral calculus last semester.

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anonymous
  • anonymous
y=+or- sqrtx , y=x/2 to make it simpler
anonymous
  • anonymous
come on guys, this isnt that hard.
anonymous
  • anonymous
wait for a while, i'm solving it.
anonymous
  • anonymous
what is really the given? it is lacking.
anonymous
  • anonymous
thats it
anonymous
  • anonymous
really?
anonymous
  • anonymous
"find the volume of the solid obtained by rotating the regions bounded by the curves about the specified line.
anonymous
  • anonymous
you have to find the point where the two curves meet, and then solve the integral from 0 to that point
anonymous
  • anonymous
they meet at (0,0)
anonymous
  • anonymous
got it.
anonymous
  • anonymous
thats one yes, and then they cross again
anonymous
  • anonymous
the answer is
anonymous
  • anonymous
8pi over 3
anonymous
  • anonymous
where do the two curves cross?
anonymous
  • anonymous
the limits are 0 and 2.
anonymous
  • anonymous
how
anonymous
  • anonymous
just substitute x=y^2 to x=2y that will become, y^2-2y=0 y(y-2)=0 y=0 y=2
anonymous
  • anonymous
okay, let me double check now
anonymous
  • anonymous
i had a mistake, the answer must be 10pi/3
anonymous
  • anonymous
almost have it
anonymous
  • anonymous
okay, i have the solution but i have a hard time encoding it.
anonymous
  • anonymous
whats (2^1.5)/(2/3) -1
anonymous
  • anonymous
i dont have my calculator :/
anonymous
  • anonymous
3.242640687
anonymous
  • anonymous
okay thats what i got... where did you get pi from?
anonymous
  • anonymous
im looking in the back of the book for the answer to see whos right.
anonymous
  • anonymous
2pi integral of (x^1/2-x/2)dx 2pi (x^3/2)/(3/2)-x^2/4, substitute x=2 2pi(2^3/2)(2/3)-2^2/4 2pi(4(2/3)-1) 2pi(8/3 - 1) 2 pi (5/3) (10pi)/3
anonymous
  • anonymous
okay i did it waaaay wrong haha
anonymous
  • anonymous
back of the book says 64pi/15
anonymous
  • anonymous
is it correct now?
anonymous
  • anonymous
is it the answer on the book?
anonymous
  • anonymous
64pi/15, so its close
anonymous
  • anonymous
okay im too tired for this, thanks for the help
anonymous
  • anonymous
you are welcome, actually i can explain it, i think i just miss some terms in my solution. by the way, do you have skype account?

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