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anonymous

  • 5 years ago

how do i graph system of linear ineaqualities with y <_ -1/2x - 1 and y > x +3

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. anonymous
    • 5 years ago
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    You graph y<= -1/2x - 1 by placing a point on -1 on the y axis and then from that point go down 1 and to the right 2. (put a point there) and then go down 1 and to the right 2 and put a point there. Since it says (=) you make the line connecting the dots a solid line. Since it says < you shade below the line.

  3. anonymous
    • 5 years ago
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    You graph y > x + 3 by placing a point on 3 on the y-axis. From that point you go up 1 and to the right 1. (put another point) from that point go up 1 and to the right 1 and put another point. Because it DOES NOT say = you put a dashed line thru the points. Because it says > you shade above that line.

  4. anonymous
    • 5 years ago
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    Where the two shades intersect ( or the area where both have been shaded on top of each other) THAT IS YOUR ANSWER.

  5. anonymous
    • 5 years ago
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    Ok thanks!

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