in a 30-60-90 triangle the shortest side ha a length of one what are the other two measurments?

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in a 30-60-90 triangle the shortest side ha a length of one what are the other two measurments?

Mathematics
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its an impossible problem,
how?
60,90

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Other answers:

the other two sides have a variable
and its length not degrees
the other two sides are sqrt(3) and 2 for the hypotenuse. shortest side is opposite the 30 degree angle.
thanks.. can you help me again?
sure
its the same kind of problem but the side is 8
ok all 30-60-90 triangles are similar. so if the ratio of the sides is always 1:sqrt(3):2 and if the side corresponding to 1 is 8 we get 8, 8sqrt(3), 16
do you know about similar triangles?
not at all.. but the answer i got was 4, sqrt(3) and it was right
not if the smallest side of the triangle was 8. which side was 8?
if the hypotenuse was 8 then you would get 4, 4sqrt(3), 8
if the shortest side is = h, then by using Law of Sines: sin30/h = sin60/x where is x= longer side (another one; across from 60 degree angle); now: \[x=h*sqrt{\3\}\] now use Pythagorean Theorem to find c... let me know if there is a problem :)
oh man that was the problem m sorry my mistake
c=2h
was the shortest side 1 for the first problem you asked or was that hypotenuse also?
no the question i last asked had the hypotenuse of eight.. the first one was correct.
allright sounds good.
thanks

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