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  • 5 years ago

how do you solve 18x^2+27x-24x-40/2x+3

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  1. anonymous
    • 5 years ago
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    first simplify the top part: 18x^2+27x-24x-40 -> this can be re-written as: 18x^2+3x-40 now, with the simplified part you have to factor it. To do so, we have find two number that multiplied is equal to -40 and another two that multiplied is 18. to confirm those 4 number check if the subtracted (subtract in this case because the last number is negative "-40") is 3. our options are: 3x6, 2x9 and 18x1 40x-1, 20x-2, 10x-4 and 5x-8 with this options, which of them have a subtraction equals to 3? ex.: (3x+10)(6x-4) = 18x^2 - 12x +60x - 40 (wrong) try another option, and keep trying until one of them workds

  2. anonymous
    • 5 years ago
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    sorry to tell u but i dont need this problem solved... i wrote it wrong and i wrote it correctly on my other post. can you help me solve the second one i posted... its above this one.... sorry but thanks for trying the problem...

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