how do you solve 18x^2+27x-24x-40/2x+3

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how do you solve 18x^2+27x-24x-40/2x+3

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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first simplify the top part: 18x^2+27x-24x-40 -> this can be re-written as: 18x^2+3x-40 now, with the simplified part you have to factor it. To do so, we have find two number that multiplied is equal to -40 and another two that multiplied is 18. to confirm those 4 number check if the subtracted (subtract in this case because the last number is negative "-40") is 3. our options are: 3x6, 2x9 and 18x1 40x-1, 20x-2, 10x-4 and 5x-8 with this options, which of them have a subtraction equals to 3? ex.: (3x+10)(6x-4) = 18x^2 - 12x +60x - 40 (wrong) try another option, and keep trying until one of them workds
sorry to tell u but i dont need this problem solved... i wrote it wrong and i wrote it correctly on my other post. can you help me solve the second one i posted... its above this one.... sorry but thanks for trying the problem...

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