disreguard my last post.. the problem is 18x^3+27x^2-24x-40/2x+3

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disreguard my last post.. the problem is 18x^3+27x^2-24x-40/2x+3

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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hmm... first you have to brake down the top part into 3 parenthesis: (x+a)(x+b)(x+c) most likely one of these parenthesis will be equal to (2x+3) so at end you will be able to cancel them both and just be left with two.
ummm. isnt there a way like to do long division or is that something else.... but what do you mean by (x+a)(x+b)(x+c)?

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