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anonymous
 5 years ago
What is the derivative of (x^2)/(x^3 +1) and why?
anonymous
 5 years ago
What is the derivative of (x^2)/(x^3 +1) and why?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1Dx(t/b) = (bt'b't)/b^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1or Dx(t/b) = Dx(t b^1) = t' b^1 + b^2 t

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.12x(x^3 +1) (x^2)3x^2  ; simplify as needed (x^3 +1)^2

angela210793
 5 years ago
Best ResponseYou've already chosen the best response.0[(x^2)/(x^3 +1)]'=(x^4+1)/(x^3+1)^2

angela210793
 5 years ago
Best ResponseYou've already chosen the best response.0(U/V)'=9U'VUV')/V^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1uvs are fine and all; but I perfor t and b to distiguish top and bottom easier

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1like the product rule: r'l + rl' , not that its hard to keep track of those lol

angela210793
 5 years ago
Best ResponseYou've already chosen the best response.0ok but i meant Dx(t/b) = (bt'b't)/b^2 must b b'tbt'/b^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1nope; bt' is first.... always has been you bring the bottom up to derive the top

angela210793
 5 years ago
Best ResponseYou've already chosen the best response.0let me see smth pls :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(U/V)'=U'VUV')/V^2 t/b = t'b  tb' / b^2 t/b = bt'  b't / b^2

angela210793
 5 years ago
Best ResponseYou've already chosen the best response.0i mean in this case u subtract them...not like...U*V which would b ok if u switched places...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1nobody switched places; they all 3 are identical

angela210793
 5 years ago
Best ResponseYou've already chosen the best response.0oops :$ :$ ...i got it.....i thought u had written smth else...sorry ^_^
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