anonymous
  • anonymous
need help with graphing problems
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
https://picasaweb.google.com/100233949726156801693/DropBox?authkey=Gv1sRgCLbAqvj885W-xAE#5608554838612174530
anonymous
  • anonymous
I did send you befor, idi u recivered?
anonymous
  • anonymous
yea i got it but cant seem to get it is there any way u could do it the work so that i could graph them

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More answers

anonymous
  • anonymous
let me check to see I still have that answer
anonymous
  • anonymous
ok
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
what nuber u need help?
anonymous
  • anonymous
on all of them
anonymous
  • anonymous
u havr graph paper?
anonymous
  • anonymous
yea
anonymous
  • anonymous
r u ok number 11?
anonymous
  • anonymous
check out Wolfram Alpha, e.g. http://www.wolframalpha.com/input/?i=y%3D2x%2B4
anonymous
  • anonymous
yea
anonymous
  • anonymous
let do 12) frist find vertex x x= (-b)/(2*a) a=-4 b=8 x=(-8)/(2*-4*) x=1 now sutitution x= 1 solve for y y=-4(1)^2 +8(1) -7 y=-4+8-7 y=-3 ( 1, -3)
anonymous
  • anonymous
-4x^2 the coefficient is nega tive tha the graph is open down , y is minimum can u set table and graph?
anonymous
  • anonymous
ok
anonymous
  • anonymous
now u set table and send I check and I work on next number
anonymous
  • anonymous
cant really set table and show dont have camera right now
anonymous
  • anonymous
look number 11the table the root (-4,-4) now number 12 u write midle line x=1 ,y=-3 up and down start next number F(x)= flug x and solve y( look the sample I send u) and graph on the grid paper
anonymous
  • anonymous
kind of get it but it will so helpful if you do them so i can check my answer getting late have to go to sleep school 2morrow
anonymous
  • anonymous
I working on 13) ok u go sleep I will do all u can print tomorrow moning, u have a printer?
anonymous
  • anonymous
yea thank u so much
anonymous
  • anonymous
Ok save the line u can find faster,good night
anonymous
  • anonymous
soory save the link not line
anonymous
  • anonymous
if I set table can u do draw the graghp?
anonymous
  • anonymous
yea
anonymous
  • anonymous
great, night
anonymous
  • anonymous
I almost done number 13 if u want wait
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
here the table number 12 u check your answer an start darw the graph
1 Attachment
anonymous
  • anonymous
14) x= 2 y= 1 grap down, y minimum I will sent table
anonymous
  • anonymous
MY internt go slow I doesn't lrt me send I try many time
anonymous
  • anonymous
my computer keep frozen don't let me send I try many time
anonymous
  • anonymous
14) -2x^2+8x-7 f f(x) --------------- 0 -7 1 -1 2 1 3 -1 4 -7 here the table 14)
anonymous
  • anonymous
15) y= x^2 -2x+5 vertex x=-(-2)\2 x=2/2 x=1 y =4 x^2 positive than the graph open up and y is maximum table: x f(x) -1 8 0 5 1 4 2 5 3 8 here number 15 include table
anonymous
  • anonymous
16) y= -x^2-4x vertex: a=-1 , b= -4 x=-(-4)\(-1*2) x = -2 plug x=-2 solve for y y = 4 -x^2 coefficient is nega tive than the graph is open down , y is minimum table: x f(x) -4 0 -3 3 -3 4 -1 3 0 0
anonymous
  • anonymous
I can send file I hope u understand
anonymous
  • anonymous
17) y=-2x^2 +4x-3 coefficient is nega tive than the graph is open down , y is minimum Vertex: x=(-4)/(-2*2) x=1 y =-1 table: x f(x) -2 -19 -1 -5 0 -3 1 -1 2 -3 3 -5
anonymous
  • anonymous
18) y= -2x^2-4x -4 coefficient is nega tive than the graph is open down , y is minimum Vertex: x=-(-4)\(-2*2) x =-1 y= -2 table: x f(x) -3 -10 -2 -4 -1 -2 0 -4 1 -10
anonymous
  • anonymous
19) y= -x^2+4x -5 coefficient is nega tive than the graph is open down , y is minimum Vertex: x =2 y=-1 table: x f(x) 0 -5 1 -2 2 -1 3 -2 4 -5
anonymous
  • anonymous
20) y= x^2-6x +10 coefficient is posi tive than the graph is open up, y is maximum Vertex x=3 y=1 table: x f(x) -1 17 0 10 1 4 3 1 5 4 6 10 7 17
anonymous
  • anonymous
r u ok?
anonymous
  • anonymous
what u need?
anonymous
  • anonymous
?

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