anonymous
  • anonymous
pls help me... a body thrown vertically up with a speed of 10 m/s from the top of a wall of height 3.45 m. The height from which another body should be dropped simultaneously such that the two bodies reach the ground at the same time is a. 40 b. 24.5 i got t=u/g =1 s (time up) h (max) =u^2/2g=100/20=5 m so total distance down is 5 + 3.45 =8.45 then what to do?? help
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
What you need here is the total time of flight for the first object. Since it vent up for 1s, as you correctly stated, it'll take 1s to reach the level of the top of the wall again. At that time it's velocity , will again be 10 m/s. The time needed to cover the rest of the way down is: \[3.45 = h = at^2/2+v*t\] solution to t is: \[t = (-v +\sqrt{v^2+4a*3.45})/2a=0.27\] So the total time of flight is: 1+1+0.27 = 2.27 s The height of an object, that takes this long to reach the ground is: \[h = at^2/2 = 10*2.27^2/2=25.76 m\] so neither is correct, but b is a lot closer.
anonymous
  • anonymous
tnx a lot 4 ur help...i was stuck..
anonymous
  • anonymous
\[2n equals 9\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.