• anonymous
pls help me... a body thrown vertically up with a speed of 10 m/s from the top of a wall of height 3.45 m. The height from which another body should be dropped simultaneously such that the two bodies reach the ground at the same time is a. 40 b. 24.5 i got t=u/g =1 s (time up) h (max) =u^2/2g=100/20=5 m so total distance down is 5 + 3.45 =8.45 then what to do?? help
Physics
• Stacey Warren - Expert brainly.com
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SOLVED
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