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moongazer
 5 years ago
How do you equate this?
9^2+x^2=4^2+(10x)^2
Please explain clearly that anyone could understand it easily.
(Guaranteed medal for a good answer)
moongazer
 5 years ago
How do you equate this? 9^2+x^2=4^2+(10x)^2 Please explain clearly that anyone could understand it easily. (Guaranteed medal for a good answer)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Combine the x^2 together on one side and the constants on another side. Set them equal to each other. x^2  (10x)^2 = 4^2  9^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Expanding it, you get x^2  100 +20x  x^2 = 4^2  9^2 The x^2 , cancels out. You are left with 100 + 20x = 4^2  9^2 20x = 4^2  9^2 + 100 = 35 x = 35/20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.09^2+x^2=4^2+(10x)^2 Sort out the constants first, so 9^2 = 81 and 4^2 = 16 Rewrite 81 + x^2 = 16 +(10x)^2 Expand (10x)^2 which gives 100 20x + x^2 Rewrite 81 + x^2 = 16 +100 20x + x^2 = 116 20x + x^2 Subtract x^2 from both sides 81 = 116 20x Subtract 116 from both sides 35 = 20x divide both sides by 5 7 = 4x Divide both sides by 4 7/4 = x
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