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sorry i think that will be *
here two conditions have to be satisfied simultaneously *. 12C3 not 12C2
smoochum, i got 115 for the solution for that other problem about multiples of 3
:O from the work we did??
@ dipankarstudy i think your first answer (12C3/24C3)+(99C3/145C3) is right , it's + not *
can you explain why is a + and not *
because the committee consists of 3 teachers OR 3 students it can't consist of both students and teachers it can only consist of 3 teachers, or it consists only of 3 students you use * if the committee consists of 3 teachers AND 3 students
oh it says 3 teachers and 3 students
both the teachers and students so *
no, it says 3 teachers/3 students , doesnt that mean 3 students OR 3 teachers?
how would you do only 1 teacher and only 1 student who are women then? adding?
oh i just simplified it dindatc XD sorry for the confusion
(12C3/24C3)+(99C3/145C3) 12C3 means 3 females are picked from 12 female teachers 99C3 means 3 females are picked from 99 female students
how about 1 teacher and 1 student?
my attempt for that one is: 12C1*12C2/24C3 * 99C1*46C2/145C3
Ways of choosing only females = (12C3 x 99C3) = 34 506 780 the ways of picking 3 teachers and 3 students with no restriction = (24C3) x (145C3)
answer to first question = [34 506 780 ] /[ 24C3 x 145C3 ] = 0.03426....