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anonymous

  • 5 years ago

really confusing, please help! a committee will consist of 3 teachers/3 students chosen from the 24 teachers & 145 students available. half of the teachers and 99 students are women. find the probability that the committee has only female members?

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  1. anonymous
    • 5 years ago
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    (12C3/24C3)+(99C3/145C3)

  2. anonymous
    • 5 years ago
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    why plus?

  3. anonymous
    • 5 years ago
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    sorry i think that will be *

  4. anonymous
    • 5 years ago
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    so (12C2)(99C3)/((24C3)*(145C3))

  5. anonymous
    • 5 years ago
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    here two conditions have to be satisfied simultaneously *. 12C3 not 12C2

  6. anonymous
    • 5 years ago
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    smoochum, i got 115 for the solution for that other problem about multiples of 3

  7. anonymous
    • 5 years ago
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    :O from the work we did??

  8. anonymous
    • 5 years ago
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    @ dipankarstudy i think your first answer (12C3/24C3)+(99C3/145C3) is right , it's + not *

  9. anonymous
    • 5 years ago
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    can you explain why is a + and not *

  10. anonymous
    • 5 years ago
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    because the committee consists of 3 teachers OR 3 students it can't consist of both students and teachers it can only consist of 3 teachers, or it consists only of 3 students you use * if the committee consists of 3 teachers AND 3 students

  11. anonymous
    • 5 years ago
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    oh it says 3 teachers and 3 students

  12. anonymous
    • 5 years ago
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    both the teachers and students so *

  13. anonymous
    • 5 years ago
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    no, it says 3 teachers/3 students , doesnt that mean 3 students OR 3 teachers?

  14. anonymous
    • 5 years ago
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    how would you do only 1 teacher and only 1 student who are women then? adding?

  15. anonymous
    • 5 years ago
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    oh i just simplified it dindatc XD sorry for the confusion

  16. anonymous
    • 5 years ago
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    (12C3/24C3)+(99C3/145C3) 12C3 means 3 females are picked from 12 female teachers 99C3 means 3 females are picked from 99 female students

  17. anonymous
    • 5 years ago
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    how about 1 teacher and 1 student?

  18. anonymous
    • 5 years ago
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    my attempt for that one is: 12C1*12C2/24C3 * 99C1*46C2/145C3

  19. anonymous
    • 5 years ago
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    Ways of choosing only females = (12C3 x 99C3) = 34 506 780 the ways of picking 3 teachers and 3 students with no restriction = (24C3) x (145C3)

  20. anonymous
    • 5 years ago
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    answer to first question = [34 506 780 ] /[ 24C3 x 145C3 ] = 0.03426....

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