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(12C3/24C3)+(99C3/145C3)

why plus?

sorry i think that will be *

so (12C2)(99C3)/((24C3)*(145C3))

here two conditions have to be satisfied simultaneously *. 12C3 not 12C2

smoochum, i got 115 for the solution for that other problem about multiples of 3

:O from the work we did??

@ dipankarstudy i think your first answer (12C3/24C3)+(99C3/145C3) is right , it's + not *

can you explain why is a + and not *

oh it says 3 teachers and 3 students

both the teachers and students so *

no, it says 3 teachers/3 students ,
doesnt that mean 3 students OR 3 teachers?

how would you do
only 1 teacher and only 1 student who are women then?
adding?

oh i just simplified it dindatc XD sorry for the confusion

how about 1 teacher and 1 student?

my attempt for that one is: 12C1*12C2/24C3 * 99C1*46C2/145C3

answer to first question = [34 506 780 ] /[ 24C3 x 145C3 ] = 0.03426....