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- anonymous

trains a and b are traveling in the same direction on parrallel tracks. train a is traveling 80 miles per hour and train b is traveling 90 miles per hour. train a passes a station at 5:10pm if train b passes the station at 5:40 pm what time will train b catch up to train A

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- anonymous

- chestercat

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- anonymous

time diff=30min.
in30 min train a goes 40mile
let in time t they catches 80t+40=90t
t=4

- anonymous

they will meet 9:10

- anonymous

AM OR PM

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- anonymous

obviously Pm

- anonymous

SORRY

- anonymous

i lol'd

- anonymous

very tired

- radar

I would like to check this out. The solution says that the trains will have traveled the same distance from the station. Train A passes the station at 5:10 pm. Four (4) hours later or at 9:10 PM it would of traveled 4 hrs at 80 mph or 320 miles.
Train B passes this station at 5.40 PM so it needs to travel 320 miles by 9:10 PM. The question is does it?? The time from 5:40 to 9:10 PM t is 3 hr 30 min or 3.5 Hr. Now for the check. The distance train B travel is 3.5 x 90= 315 miles Note this does not equal 320 miles. At 9:10 PM those trains are 5 miles apart. Uh Oh

- radar

Somebody needs to go back to the drawing board (hope it's not me lol)

- radar

The time would be 9:40
fast train would travel 4 hrs @ 90 mph for 360 miles.
sloe train would travel 4.5 hrs @ 80 mph for 360 miles

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