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anonymous

  • 5 years ago

nCk= The combinations of n taken k at a time. which of the following is equal to 11C8? a) 11!/3! b) 11!/11!8! c) 11!/8!3! d) 11!/8!

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  1. anonymous
    • 5 years ago
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    Is it a..?

  2. anonymous
    • 5 years ago
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    no c

  3. anonymous
    • 5 years ago
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    nCr = n!/r!(n-r)!

  4. anonymous
    • 5 years ago
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    c is the right choice

  5. anonymous
    • 5 years ago
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    nPk = n!/(n-k)1

  6. anonymous
    • 5 years ago
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    right

  7. anonymous
    • 5 years ago
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    dont be confused between permutations and combination , both are different

  8. anonymous
    • 5 years ago
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    yep agreed :D

  9. anonymous
    • 5 years ago
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    I'm confused between the two formulas and two answers

  10. anonymous
    • 5 years ago
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    11C8= 11! ----- 8!*3!

  11. anonymous
    • 5 years ago
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    i have a way combination : we only select the items permutation: we select and we also arrange the items

  12. anonymous
    • 5 years ago
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    umm .. sorry that will be when u do problems of probability

  13. anonymous
    • 5 years ago
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    but metarock ur definition is right

  14. anonymous
    • 5 years ago
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    ya but chizzle was confused in the formulas , a different context though

  15. anonymous
    • 5 years ago
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    Ah, just found a way to remember (P)ermutation ... (P)osition matters both begin with P

  16. anonymous
    • 5 years ago
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    (C)ombination and (C)ounting (or selecting) ;-)

  17. anonymous
    • 5 years ago
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    So then it is 11!/8!3! ?

  18. anonymous
    • 5 years ago
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    yups

  19. anonymous
    • 5 years ago
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    Okay thank you all for the help/formulas/and differences between them

  20. anonymous
    • 5 years ago
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    ur welcome

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spraguer (Moderator)
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