nCk= The combinations of n taken k at a time. which of the following is equal to 11C8? a) 11!/3! b) 11!/11!8! c) 11!/8!3! d) 11!/8!

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nCk= The combinations of n taken k at a time. which of the following is equal to 11C8? a) 11!/3! b) 11!/11!8! c) 11!/8!3! d) 11!/8!

Mathematics
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Is it a..?
no c
nCr = n!/r!(n-r)!

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Other answers:

c is the right choice
nPk = n!/(n-k)1
right
dont be confused between permutations and combination , both are different
yep agreed :D
I'm confused between the two formulas and two answers
11C8= 11! ----- 8!*3!
i have a way combination : we only select the items permutation: we select and we also arrange the items
umm .. sorry that will be when u do problems of probability
but metarock ur definition is right
ya but chizzle was confused in the formulas , a different context though
Ah, just found a way to remember (P)ermutation ... (P)osition matters both begin with P
(C)ombination and (C)ounting (or selecting) ;-)
So then it is 11!/8!3! ?
yups
Okay thank you all for the help/formulas/and differences between them
ur welcome

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