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anonymous

  • 5 years ago

how many 3 digit #s can you make with 3-9 if the resulting number has to be divisible by 3?

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  1. anonymous
    • 5 years ago
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    easy

  2. anonymous
    • 5 years ago
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    I guess they are assuming no repeated digits

  3. anonymous
    • 5 years ago
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    yeah since that's just 3* whatever

  4. anonymous
    • 5 years ago
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    so the last position be either 3,6,9 ( so we have 3ways ) 3 x 7 x 6

  5. anonymous
    • 5 years ago
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    3-9 = 3,4,5,6,7,8,9 = 7 digits

  6. anonymous
    • 5 years ago
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    i think it's from 309 to 399, all is divisible by 3 so it's 10

  7. anonymous
    • 5 years ago
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    ergh no, 319 isnt divisivle by 3

  8. anonymous
    • 5 years ago
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    wait I wrotw is wrong

  9. anonymous
    • 5 years ago
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    neither 49

  10. anonymous
    • 5 years ago
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    309, 339,369,and 399. the answer is 4

  11. anonymous
    • 5 years ago
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    sum of the digits must be divisible by 3

  12. anonymous
    • 5 years ago
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    yeah

  13. anonymous
    • 5 years ago
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    yeh, if I new that then it would be easier ^

  14. anonymous
    • 5 years ago
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    so how would you proceed with the problem knowing its the sum of the digits that makes it divisible by 3

  15. anonymous
    • 5 years ago
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    r u consider all the numbers between 3 and 9?

  16. anonymous
    • 5 years ago
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    yeah 3 4 5 6 7 8 9

  17. anonymous
    • 5 years ago
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    oh if so, then my answer is wrong, sorry i misunderstood the question

  18. anonymous
    • 5 years ago
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    haha that's ok

  19. anonymous
    • 5 years ago
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    is it between 3 and 9 or from 3 to 9?

  20. anonymous
    • 5 years ago
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    from 3 to 9 so 3 and 9 inclusive

  21. anonymous
    • 5 years ago
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    the last digit wuold be 12 becacause 12 divided by 3 would bring 4

  22. anonymous
    • 5 years ago
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    1 and 2 are not included

  23. anonymous
    • 5 years ago
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    nope 1 and 2 aren't included or 0 either

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