anonymous
  • anonymous
how many 3 digit #s can you make with 3-9 if the resulting number has to be divisible by 3?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
easy
anonymous
  • anonymous
I guess they are assuming no repeated digits
anonymous
  • anonymous
yeah since that's just 3* whatever

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anonymous
  • anonymous
so the last position be either 3,6,9 ( so we have 3ways ) 3 x 7 x 6
anonymous
  • anonymous
3-9 = 3,4,5,6,7,8,9 = 7 digits
anonymous
  • anonymous
i think it's from 309 to 399, all is divisible by 3 so it's 10
anonymous
  • anonymous
ergh no, 319 isnt divisivle by 3
anonymous
  • anonymous
wait I wrotw is wrong
anonymous
  • anonymous
neither 49
anonymous
  • anonymous
309, 339,369,and 399. the answer is 4
anonymous
  • anonymous
sum of the digits must be divisible by 3
anonymous
  • anonymous
yeah
anonymous
  • anonymous
yeh, if I new that then it would be easier ^
anonymous
  • anonymous
so how would you proceed with the problem knowing its the sum of the digits that makes it divisible by 3
anonymous
  • anonymous
r u consider all the numbers between 3 and 9?
anonymous
  • anonymous
yeah 3 4 5 6 7 8 9
anonymous
  • anonymous
oh if so, then my answer is wrong, sorry i misunderstood the question
anonymous
  • anonymous
haha that's ok
anonymous
  • anonymous
is it between 3 and 9 or from 3 to 9?
anonymous
  • anonymous
from 3 to 9 so 3 and 9 inclusive
anonymous
  • anonymous
the last digit wuold be 12 becacause 12 divided by 3 would bring 4
anonymous
  • anonymous
1 and 2 are not included
anonymous
  • anonymous
nope 1 and 2 aren't included or 0 either

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