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LeoMessi

  • 4 years ago

Would be the first derivative of this function with: F(X)=(1+2x+x^3)^1/4 ?

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  1. Owlfred
    • 4 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. fauxshaux
    • 4 years ago
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    \[f(x) = (1 + 2*x + x^3)^{1/4}\]

  3. fauxshaux
    • 4 years ago
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    OK. \[f'(x) = (1/4)(1+2*x+x^3)^{-3/4} * ( 1 + 2 + 3x^2 )\]

  4. fauxshaux
    • 4 years ago
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    the general concept is: g(f(x))'=g'(f(x)).f'(x)

  5. LeoMessi
    • 4 years ago
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    oh, ok, I see. thanks

  6. isavita
    • 4 years ago
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    f'(x)=[(1/4)(1+2∗x+x3)^−3/4].(2+3x^2)

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