Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by
S(t) = 68 − 20 log (t + 1), t ≥ 0.
What was the average score when they initially took the test, t = 0?
Round your answer to a whole percent, if necessary.

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log(1)=0, so at t=0 we have
S(0)=68-20*0
S(0)=68

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