A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

Determine the parametric equations of the tangent line to the curve r(t) =< cos 2t; sin 3t; sin 4t > when t = pi/4

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    we want the time derivative of r(t) r'(t)=<-2sin(2t), 3cos(3t), 4cos(4t)> now find r'(pi/4) r'(pi/4)=<-2, -3sqrt(2)/2, -4> so we have a direction vector, now we want a point on the line. We can use r(pi/4) r(pi/4)=<0, sqrt(2)/2, 0> so the equation of the tangent line is T=<-2s, sqrt(2)/2-(3sqrt(2)/2)*s, -4s> where s is an arbitrary parameter.

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I took the derivative but was unsure where to go from there, thanks!

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    in the last equation why the variables swapped?

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so it's not confused with t, since it doesn't need to be the same variable.

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.