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anonymous
 5 years ago
Hey everyone, need help finding the arc length of the curve y^2=x^3 from (0,0) to (1/4,1/8).
anonymous
 5 years ago
Hey everyone, need help finding the arc length of the curve y^2=x^3 from (0,0) to (1/4,1/8).

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know the formula and I think y'=(3x^2)/(2y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me try this, see if it works. \[y=x^\frac{3}{2}\] yes?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok right, do we only take the +x^3/2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y'=\frac{3}{2}x^\frac{1}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y = x^(3/2) y' = 3/2*x^1/2 (y')^2 = 9/4*x integrate sqrt(1+9/4*x) from 1/8 to 1/4 use usub if you have to

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Rim would it not be from 0 to 1/4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh sorry yes 0 to 1/4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we are going from (0,0) to (1/8,1/4) so it is ok yes? maybe i am wrong, but i will graph it. in any case we have to integrate \[\int_0^{\frac{1}{8}} \sqrt{1\frac{9}{4}x} dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops you are right it is 1/4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0anti derivative is \[\frac{(49x)^\frac{3}{2}}{27}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and integral is \[\frac{8}{27}\frac{7\sqrt{7}}{216}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you guys get .2824?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me get a calculator i will check

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no in fact i got .21055...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, but isnt it also sqrt(1+(9/4)x)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well i guess i messed up hold on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are right and i am wrong (0ften the case)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take advantage of Wolfram alpha it is a very useful tool

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i put  where i should have had +. sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no problem thanks for the help guys

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just why do we pick positive sqrt all the time?
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