## anonymous 5 years ago Solve the equation: (sin^-1 x) - cos ^-1(sqrt(3)/3) = 0 What do I do with sin after I convert cos?

1. anonymous

use $\cos^{-1} A+\cos^{-1} B=\cos^{-1} (AB+\sqrt{1-B^2}\sqrt{1-A^2})$

2. anonymous

I don't understand, I keep getting strange answers

3. anonymous

$\sin^{-1} (x) -\cos^{-1} (\sqrt{3}/3) =0$ $\sin^{-1} (x) =\cos^{-1} (\sqrt{3}/3)$ $x =\sin (\cos^{-1} (\sqrt{3}/3) )$ ?