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Round to the nearst two decimal places

calculator exercise. replace t by 4, and 24. i will write it if you like

is this log base ten?

i dont get it

t = time in months yes?

so for the first one put
\[S(4)=68-20log(4+1)=68-20log(5)\]

in other words put 4 where you see a t and then compute

you need a calculator to find log(5)

i got 54.02

let me try

\[S(24)=68-20log(25)=...\]

i let me know if you have an answer

okay me to so for 24 months its
40.04

sound right

hold on i will compute

yup that is what i got

now we have to find when S = 50. do you know how to do that one?

no

ok so far?

no , why did you put 68-50

so we have arrived via some algebra at
\[log(t+1)=.9\] is that ok so far?

yes i think im getting it

you would get \[x=.9\] and here \[x=log(t+1)\] so \[log(t+1)=.9\]

we are not done yet, though because we have to solve for t.

okay im following you

\[log(x)=y \]
\[10^y=x\]

what i meant to say was
\[log(x)=y\] means the same thing as
\[10^y=x
\]

here we have \[log(t+1)=.9\]
so
\[10^{.9}=t+1\]

to find
\[10^{.9}\] in need a calculator. then to get t by itself subtract 1.

let me know what you get.

6.94 sound right

its wrong???