A community for students.
Here's the question you clicked on:
 0 viewing
Ackbar
 4 years ago
What is the product rule?
Ackbar
 4 years ago
What is the product rule?

This Question is Closed

Owlfred
 4 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

LeoMessi
 4 years ago
Best ResponseYou've already chosen the best response.1product rule is for finding the derivative of the product of two functions: \[(f(x) * g(x))' = f(x) * g'(x) + g(x) * f'(x)\]

fauxshaux
 4 years ago
Best ResponseYou've already chosen the best response.1yes, and you can expand this concept to products of more than 2 functions...just remember to take the derivative of each product...so one derivative per term...

Ackbar
 4 years ago
Best ResponseYou've already chosen the best response.0i'm sort of lost for the application to more than 2 functions... :/

fauxshaux
 4 years ago
Best ResponseYou've already chosen the best response.1\[(f(x) * g(x) * h(x))' = f(x) * h(x) *g'(x) + g(x) * h(x) * f'(x) + g(x) * f(x) *h'(x)\]

Ackbar
 4 years ago
Best ResponseYou've already chosen the best response.0oooh, i was having trouble visualizing that one. thanks

smbogle
 4 years ago
Best ResponseYou've already chosen the best response.0I think by taking the change variation of the area as 2pi.r, we get what we are looking for by integrating.

TigerHound
 4 years ago
Best ResponseYou've already chosen the best response.0\[(uv)\prime = u \prime \times v +v \prime \times u \]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.