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anonymous

  • 5 years ago

lim (e^(-6 x)cos(x)) x-> infinity

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  1. anonymous
    • 5 years ago
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    0

  2. anonymous
    • 5 years ago
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    is it e^(-6 x) *cos(x) or e^((-6 x)cos(x))

  3. anonymous
    • 5 years ago
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    \[\frac{cos(x)}{e^{6x}}\] cosine is bounded by one and the denominator goes to infinity lickedy split

  4. anonymous
    • 5 years ago
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    the first one

  5. anonymous
    • 5 years ago
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    confused. what is the difference between those two Andras?

  6. anonymous
    • 5 years ago
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    its e^(-6x) * (cosx)

  7. anonymous
    • 5 years ago
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    \[cosx/e ^{6x}\]

  8. anonymous
    • 5 years ago
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    ans is zero

  9. anonymous
    • 5 years ago
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    could you explain it please

  10. anonymous
    • 5 years ago
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    lim x---> infinity= any value in the interval [-1.1] say A lim x---> infinity e^6x=infinity A/infinity=0

  11. anonymous
    • 5 years ago
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    thankyou, how do i give a medals for the answers

  12. anonymous
    • 5 years ago
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    click good answer against the name :P

  13. anonymous
    • 5 years ago
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    see, i awarded to u :)

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spraguer (Moderator)
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