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julie Group Title How exactly do these procedures work? (define (square x) (exp (double (log x)))) (define (double x) (+ x x)) 3 years ago 3 years ago

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1. Owlfred

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

2. shadowfiend

Pretty staightforward; remember how logs/exponents work: \begin{align} exp(double (log x)) &= e^{2 \ln x}\\ &= e^{\ln x^2}\\ &= x^2 \end{align} Have a look at http://en.wikipedia.org/wiki/Logarithm for more.