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julie
Group Title
How exactly do these procedures work?
(define (square x)
(exp (double (log x))))
(define (double x) (+ x x))
 3 years ago
 3 years ago
julie Group Title
How exactly do these procedures work? (define (square x) (exp (double (log x)))) (define (double x) (+ x x))
 3 years ago
 3 years ago

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Owlfred Group TitleBest ResponseYou've already chosen the best response.0
Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!
 3 years ago

shadowfiend Group TitleBest ResponseYou've already chosen the best response.4
Pretty staightforward; remember how logs/exponents work: \[\begin{align} exp(double (log x)) &= e^{2 \ln x}\\ &= e^{\ln x^2}\\ &= x^2 \end{align}\] Have a look at http://en.wikipedia.org/wiki/Logarithm for more.
 3 years ago
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