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Owlfred
 3 years ago
Best ResponseYou've already chosen the best response.0Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

fauxshaux
 3 years ago
Best ResponseYou've already chosen the best response.1i've seen this before dw=(∂w/∂z)dz+(∂w/∂x)dx+(∂w/∂y)dy

fauxshaux
 3 years ago
Best ResponseYou've already chosen the best response.1\[(\partial w/ \partial z)_{(0,0,1)} = e^{0+0} = 1, (\partial w/ \partial x)_{(0,0,1)} = 1. e^{0+0} = 1, (\partial w/\partial y)_{(0,0,1)} = 1. e ^{0+0} = 1\]
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