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anonymous
 5 years ago
Find the Taylor series of 1/(1x)^2 about a=0
anonymous
 5 years ago
Find the Taylor series of 1/(1x)^2 about a=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01+2 x+3 x^2+4 x^3+5 x^4+6 x^5+O(x^6)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0saubhik has it without finding derivatives, evaluating etc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just by noting that \[\frac{1}{(1x)^2}\] is the derivative of \[\frac{1}{1x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why dont you get alternating signs? when you differentiate 1/(1x)^2 you get  sign

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oop i meant \[\frac{1}{1x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the well known formula for summing a geometric sequence \[\frac{1}{1x}=1+x+x^2+x^3+...\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0differentiate term by term to get the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh hell, I see... there are 2 minus signs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh in the chain rule? yes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tripped me up the first time i saw it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:) Now I get it, I just could not see why it is not 12 x+3 x^24 x^3+ and so on. but I see it now
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