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Maddiie

  • 5 years ago

Find an equation of the line satisfying the conditions given. Express your answer in standard form. Parallel to 3x-y=-5 and passing through(1-,0)

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  1. anonymous
    • 5 years ago
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    3x-y=3

  2. radar
    • 5 years ago
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    Do you know what the slope is for your line?

  3. anonymous
    • 5 years ago
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    if the given is (-1,0) then 3x-y=-3

  4. radar
    • 5 years ago
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    Express you equation in the slope intercept form y=3x+5. The slope is the coefficient of x or a +3. The slope of the parallel line must be +3 also. This is the rule.

  5. radar
    • 5 years ago
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    You have been given one point for this parallel, that is the point (-1,0). Or I think you have....that point looks funny with the - stuck between the x and y position like that. From your study of the line equation,you know slope or m=\[\Delta y \over \Delta x\]

  6. radar
    • 5 years ago
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    so 3= (y-0)/(x+1) using the algebra you have learned this then becomes y=3x+3 but your problem stated it wanted it expressed in standard form which would be: 3x-y+3=0 for the standard Ax+By+C=0

  7. radar
    • 5 years ago
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    Hope this helps, good luck in your pursuit of knowledge.

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