anonymous
  • anonymous
2z^2+7z-15=0 What is the solution set for the equation? a. {5,-3/2} b. {-5,3/2} c. {-5, 3} d. {5,-3}
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Two ways to solve this: a) Solve the equation and look for a pair that contains both of those b) Try to plug in each solution from each set and choose the solution set whose all solutions really solve the equation
anonymous
  • anonymous
Clarification for step b: if you plug in e.g. z=5 and find out that the equation holds, you know the answer is either a or d. If it doesn't hold, it is either b or c. Doing similar reasoning for other values enables you to quickly rule out incorrect alternatives.
anonymous
  • anonymous
Okay. Thanks for clearing that up.

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anonymous
  • anonymous
Since these look like school problems, see if it can be factored first. This one factors as follows: (z + 5) (2 z - 3)

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