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anonymous

  • 5 years ago

2z^2+7z-15=0 What is the solution set for the equation? a. {5,-3/2} b. {-5,3/2} c. {-5, 3} d. {5,-3}

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  1. anonymous
    • 5 years ago
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    Two ways to solve this: a) Solve the equation and look for a pair that contains both of those b) Try to plug in each solution from each set and choose the solution set whose all solutions really solve the equation

  2. anonymous
    • 5 years ago
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    Clarification for step b: if you plug in e.g. z=5 and find out that the equation holds, you know the answer is either a or d. If it doesn't hold, it is either b or c. Doing similar reasoning for other values enables you to quickly rule out incorrect alternatives.

  3. anonymous
    • 5 years ago
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    Okay. Thanks for clearing that up.

  4. anonymous
    • 5 years ago
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    Since these look like school problems, see if it can be factored first. This one factors as follows: (z + 5) (2 z - 3)

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