I want to know if i am rite 4. The total consumption of fossil fuels in the United States per year can be represented by the function C(x) = 0.0439x3 – 1.4911x2 + 14.224x + 41.76, where x is the number of years after 1970, and C(x) represents the amount of energy consumed in quadrillions of BTUs (or “quads”). In 1979, the U.S. consumed 81 quads of energy. Subtract C(x) – 81 and write down the resulting function. Since you know that 9 is a root of this function, find the other two roots. In what year after 1979 did the U.S. consumption of energy also reach 81 quads?

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I want to know if i am rite 4. The total consumption of fossil fuels in the United States per year can be represented by the function C(x) = 0.0439x3 – 1.4911x2 + 14.224x + 41.76, where x is the number of years after 1970, and C(x) represents the amount of energy consumed in quadrillions of BTUs (or “quads”). In 1979, the U.S. consumed 81 quads of energy. Subtract C(x) – 81 and write down the resulting function. Since you know that 9 is a root of this function, find the other two roots. In what year after 1979 did the U.S. consumption of energy also reach 81 quads?

Mathematics
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looks good to me. want the computation?
can you work this problem out?
well except it is not what i get

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bare with me, i going write i have so far
let me try again and make sure i have it correct
C(x) = 0.0439x3 – 1.4911x2 + 14.224x + 41.76
so what you do is, substract 81 from 41.79
\[C(x)=.0439x^3-1.4991x^2+14.224x+41.76\] is that right?
i mean before you subtract is that correct?
you going have c(c) 0.0439x^3-1.4911x^2+14.224-39.28 now you use syntethic divicion, we know 9 is a root of this function
yes that would be correct. if C(9) = 81
9] 0.0439 -1.4911 +14.224 -39.28
but it doesn't seem to be according to my calculation let me check again
no the first question
when you do syntethic division, you get 0
then you are correct!
and teh giving you an extreme equation, and know you can find both root, 0.0439^2-1.096x+8.36
you did the syntethinc division, and you got 0, correct?
you did the syntethinc division, and you got 0, correct?
you did the syntethinc division, and you got 0, correct?
must be typing something in wrong because i do not get zero
ok , type what you doing
close, but i get C(9)=-.04 but that is probably close enough. you get 0 exactly?
so you get 0?
close to 0 , is not enough..
ooho i see
41.76-81=-39.24 not -39.28
le't try it again, 9] 0.0439 -1.4911 +14.224 +39.28
last number should be 39.24
use your calculator, i dont knohere mine is
then it will work
i did and it works
oh good, oh graph, yeah is -39.24, i thought it was an 8
whew. then you get 0 i checked already
get \[0.04390*x^2-1.096x+4.36\]
yeah, now what, guadratic formula?
yes what a pain. hold on and i will cheat if you like
lol
ikr, better then factoring at least...
looks like x=20 or x = 4.966 rounded
a miracle. 20 is exact!
so going back to the problem, those are the root, you did quadratic formula?lol
we must bei n the right tract
so it must factor as \[(x-20)(.0439x-.218)\]
no i didn't use the quadratic formula because i would have no patience for that
i used maple
lol, so wee know both root that were missing, the is really the aswner?
yup that is it
just changing them to word, and the will do it, thx man.
must be. you can check easily (more or less) that 20 is a zero of \[.0439x^2-1.096x+4.36\] so as you know it must factor as \[(x-20)(something)\] and you have no choice for the something
good luck
oh crap, we are not,done, remember it ask you in qhat yesterday,
oh crap, we are not,done, remember it ask you in qhat yesterday,
oh crap, we are not,done, remember it ask you in qhat yesterday,
oh crap, we are not,done, remember it ask you in qhat yesterday,
oh crap, we are not,done, remember it ask you in qhat yesterday,
lol, lagg, year*
lol, lagg, year*
you still here?

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