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anonymous
 5 years ago
I want to know if i am rite
4. The total consumption of fossil fuels in the United States per year can be represented by the function C(x) = 0.0439x3 – 1.4911x2 + 14.224x + 41.76, where x is the number of years after 1970, and C(x) represents the amount of energy consumed in quadrillions of BTUs (or “quads”). In 1979, the U.S. consumed 81 quads of energy.
Subtract C(x) – 81 and write down the resulting function. Since you know that 9 is a root of this function, find the other two roots. In what year after 1979 did the U.S. consumption of energy also reach 81 quads?
anonymous
 5 years ago
I want to know if i am rite 4. The total consumption of fossil fuels in the United States per year can be represented by the function C(x) = 0.0439x3 – 1.4911x2 + 14.224x + 41.76, where x is the number of years after 1970, and C(x) represents the amount of energy consumed in quadrillions of BTUs (or “quads”). In 1979, the U.S. consumed 81 quads of energy. Subtract C(x) – 81 and write down the resulting function. Since you know that 9 is a root of this function, find the other two roots. In what year after 1979 did the U.S. consumption of energy also reach 81 quads?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0looks good to me. want the computation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you work this problem out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well except it is not what i get

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0bare with me, i going write i have so far

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me try again and make sure i have it correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0C(x) = 0.0439x3 – 1.4911x2 + 14.224x + 41.76

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what you do is, substract 81 from 41.79

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[C(x)=.0439x^31.4991x^2+14.224x+41.76\] is that right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean before you subtract is that correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you going have c(c) 0.0439x^31.4911x^2+14.22439.28 now you use syntethic divicion, we know 9 is a root of this function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes that would be correct. if C(9) = 81

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.09] 0.0439 1.4911 +14.224 39.28

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but it doesn't seem to be according to my calculation let me check again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no the first question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you do syntethic division, you get 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you are correct!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and teh giving you an extreme equation, and know you can find both root, 0.0439^21.096x+8.36

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you did the syntethinc division, and you got 0, correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you did the syntethinc division, and you got 0, correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you did the syntethinc division, and you got 0, correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0must be typing something in wrong because i do not get zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok , type what you doing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0close, but i get C(9)=.04 but that is probably close enough. you get 0 exactly?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0close to 0 , is not enough..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.041.7681=39.24 not 39.28

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0le't try it again, 9] 0.0439 1.4911 +14.224 +39.28

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0last number should be 39.24

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use your calculator, i dont knohere mine is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh good, oh graph, yeah is 39.24, i thought it was an 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whew. then you get 0 i checked already

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0get \[0.04390*x^21.096x+4.36\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, now what, guadratic formula?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes what a pain. hold on and i will cheat if you like

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ikr, better then factoring at least...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0looks like x=20 or x = 4.966 rounded

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a miracle. 20 is exact!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so going back to the problem, those are the root, you did quadratic formula?lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we must bei n the right tract

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it must factor as \[(x20)(.0439x.218)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i didn't use the quadratic formula because i would have no patience for that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, so wee know both root that were missing, the is really the aswner?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just changing them to word, and the will do it, thx man.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0must be. you can check easily (more or less) that 20 is a zero of \[.0439x^21.096x+4.36\] so as you know it must factor as \[(x20)(something)\] and you have no choice for the something

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh crap, we are not,done, remember it ask you in qhat yesterday,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh crap, we are not,done, remember it ask you in qhat yesterday,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh crap, we are not,done, remember it ask you in qhat yesterday,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh crap, we are not,done, remember it ask you in qhat yesterday,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh crap, we are not,done, remember it ask you in qhat yesterday,
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