## anonymous 5 years ago How do the areas compare when the dimensions of one are 3 times the dimension of the other?

1. Owlfred

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2. anonymous

if you have a one by one square the area is 1. if you have a 3 by 3 square the area is 9. so it varies with the square of the side

3. anonymous

if your square is x by x then area is $x^2$ if your square is 3x by 3x then area is $(3x)^2=9x^2$

4. anonymous

so second is 9 times the first.

5. anonymous

but one square is 15 cm and 1 is 135 cm

6. anonymous

if one square is 15 cm i assume you mean the side is 15cm yes?

7. anonymous

no the area

8. anonymous

oh the area is 15 square cm so the side is $\sqrt{15}$

9. anonymous

but the question is How do the areas compare when the dimensions of one are 3 times the dimension of the other?

10. anonymous

as i said, if one has side x and the other 3x the area of the second is 9 times the area of the first . just like 135 is 9 times 15

11. anonymous

so the answer is, "if the dimensions of one square are 3 times the dimensions of the other, then the area of the bigger square is 9 times the area of the smaller."

12. anonymous

thankss <3

13. anonymous

Wait sorry. The question was: How do the areas of two parallelograms compare when the dimensions of one are 3 times the dimension of the other?