anonymous
  • anonymous
How do the areas compare when the dimensions of one are 3 times the dimension of the other?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Owlfred
  • Owlfred
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anonymous
  • anonymous
if you have a one by one square the area is 1. if you have a 3 by 3 square the area is 9. so it varies with the square of the side
anonymous
  • anonymous
if your square is x by x then area is \[x^2\] if your square is 3x by 3x then area is \[(3x)^2=9x^2\]

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anonymous
  • anonymous
so second is 9 times the first.
anonymous
  • anonymous
but one square is 15 cm and 1 is 135 cm
anonymous
  • anonymous
if one square is 15 cm i assume you mean the side is 15cm yes?
anonymous
  • anonymous
no the area
anonymous
  • anonymous
oh the area is 15 square cm so the side is \[\sqrt{15}\]
anonymous
  • anonymous
but the question is How do the areas compare when the dimensions of one are 3 times the dimension of the other?
anonymous
  • anonymous
as i said, if one has side x and the other 3x the area of the second is 9 times the area of the first . just like 135 is 9 times 15
anonymous
  • anonymous
so the answer is, "if the dimensions of one square are 3 times the dimensions of the other, then the area of the bigger square is 9 times the area of the smaller."
anonymous
  • anonymous
thankss <3
anonymous
  • anonymous
Wait sorry. The question was: How do the areas of two parallelograms compare when the dimensions of one are 3 times the dimension of the other?

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