anonymous
  • anonymous
if f(x)=x^2 -1. what is the equation for f^-1(x) ....f^-1(x)= +/- (squareroot all)x+1 ...f^-1(x)= +/- (squareroot all )x-1 ....f^-1(x)= +/- (squareroot x only) x+1 ....f^-1(x)= +/- (squareroot x only) x-1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[y=x^2-1\] switch x and y \[x=y^2-1\] solve for y \[x+1=y^2\] \[y=\pm\sqrt{x+1}\]
anonymous
  • anonymous
but this is not a function, so cannot be one of the answers. did they restrict the domain of f?
anonymous
  • anonymous
nope

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anonymous
  • anonymous
then there is a mistake here some place. you cannot write \[f^{-1}(x)=\pm\sqrt{x+1}\] because a function cannot have two answers. on the other hand you are not allowed just to pick one

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