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anonymous

  • 5 years ago

using a graphing calculator, find the real zeros of the function. f(x) = x^6-8x^5+15x^3-2x^2+9

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  1. anonymous
    • 5 years ago
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    looks like there is one just below 8 say at 7.8

  2. anonymous
    • 5 years ago
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    another at about 1.6

  3. anonymous
    • 5 years ago
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    and if you zoom in you will see that those are the only two. it looks at first glance like there are more but there are not. looks like one around -1 but it is an illusion, the graph stays above the x-axis there. very tricky

  4. anonymous
    • 5 years ago
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    ok. i got it. took me a minute. thanks

  5. anonymous
    • 5 years ago
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    took me a minute too. welcome

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spraguer (Moderator)
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