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anonymous
 5 years ago
Let f(x)=4x2 and g(x)=5x6. find F(little black circle ) g and state it's domain
anonymous
 5 years ago
Let f(x)=4x2 and g(x)=5x6. find F(little black circle ) g and state it's domain

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0they all are real numbers but is 6 or 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no domain is all real numbers. \[f(g(x))=f(5x6)=4(5x6)2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now we can multiply and combine like terms \[f(g(x))=4(5x6)2=20x+242=20x+22\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is a line, so domain all real numbers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.034 or 12 are in the answer somewhere

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i don't see 34 or 14 anywhere in \[f(g(x))\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0possible answers ..20x^2+14x+12 all real except ..8x^2+34x30 all real except 1 ...8x^2+3430 all real ...20x^2+14x+12 all real

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OOOOOOhhhhhhhhhhhhhhhhh

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[fg(x) not f(g(x))\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.020x^2+14x+12 all real except 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well if that is it, i am right. if it is f times g then one of those is the answer. but that open circle does not mean mulitply

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no it would not be all real except 6 because it is a polynomial so it would be all real numbers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no it is a close circle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope you are right sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0domain all real numbers
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